Logic Implementation
en_o = (A xnor B) and en_i;
If (skip_i = ‘1’) then skip_o = ‘1’; else skip_o = en_i and (A and B’) ; end if;
Can use a K-map to simplify this logic.
The skip_o of the LAST bit is the AgtB signal!
The en_o of the LAST bit is the AeqB signal!